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2133241030147 is a prime number
BaseRepresentation
bin11111000010101111000…
…100101110011000000011
321112221021020100111010111
4133002233010232120003
5234422334200431042
64311555234412151
7310056462400633
oct37025704563003
97487236314114
102133241030147
1175277aa47927
122a552a131057
13126218a42106
147536c5846c3
153a755646517
hex1f0af12e603

2133241030147 has 2 divisors, whose sum is σ = 2133241030148. Its totient is φ = 2133241030146.

The previous prime is 2133241030133. The next prime is 2133241030153. The reversal of 2133241030147 is 7410301423312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2133241030147 - 231 = 2131093546499 is a prime.

It is a super-3 number, since 3×21332410301473 (a number of 38 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (2133241030157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066620515073 + 1066620515074.

It is an arithmetic number, because the mean of its divisors is an integer number (1066620515074).

Almost surely, 22133241030147 is an apocalyptic number.

2133241030147 is a deficient number, since it is larger than the sum of its proper divisors (1).

2133241030147 is an equidigital number, since it uses as much as digits as its factorization.

2133241030147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 2133241030147 its reverse (7410301423312), we get a palindrome (9543542453459).

The spelling of 2133241030147 in words is "two trillion, one hundred thirty-three billion, two hundred forty-one million, thirty thousand, one hundred forty-seven".