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21333120000 = 21035441271
BaseRepresentation
bin10011110111100011…
…011001010000000000
32001001202000210002120
4103313203121100000
5322142234320000
613444510444240
71353440346063
oct236743312000
961052023076
1021333120000
119057a98895
124174503680
13201c93aa3a
1410653888da
1584ccee6a0
hex4f78d9400

21333120000 has 440 divisors, whose sum is σ = 73054515072. Its totient is φ = 5529600000.

The previous prime is 21333119989. The next prime is 21333120013. The reversal of 21333120000 is 2133312.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 78719865 + ... + 78720135.

Almost surely, 221333120000 is an apocalyptic number.

21333120000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21333120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (36527257536).

21333120000 is an abundant number, since it is smaller than the sum of its proper divisors (51721395072).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21333120000 is an equidigital number, since it uses as much as digits as its factorization.

21333120000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 355 (or 322 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 15.

Adding to 21333120000 its reverse (2133312), we get a palindrome (21335253312).

21333120000 divided by its reverse (2133312) gives a 4-th power (10000 = 104).

The spelling of 21333120000 in words is "twenty-one billion, three hundred thirty-three million, one hundred twenty thousand".