Base | Representation |
---|---|
bin | 110000100000011001001101… |
… | …111011110100110111100111 |
3 | 1000222100101001002112100021222 |
4 | 300200121031323310313213 |
5 | 210430214104234332444 |
6 | 2033415304302130555 |
7 | 62635516042106501 |
oct | 6040311573646747 |
9 | 1028311032470258 |
10 | 213332333120999 |
11 | 61a79809536744 |
12 | 1bb1529a880a5b |
13 | 92061ca60b851 |
14 | 3a974a9006d71 |
15 | 199e3e4773eee |
hex | c2064def4de7 |
213332333120999 has 4 divisors (see below), whose sum is σ = 213332751121080. Its totient is φ = 213331915120920.
The previous prime is 213332333120947. The next prime is 213332333121097. The reversal of 213332333120999 is 999021333233312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213332333120999 - 28 = 213332333120743 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 213332333120999.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213332333125999) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 208233557 + ... + 209255534.
It is an arithmetic number, because the mean of its divisors is an integer number (53333187780270).
Almost surely, 2213332333120999 is an apocalyptic number.
213332333120999 is a deficient number, since it is larger than the sum of its proper divisors (418000081).
213332333120999 is an equidigital number, since it uses as much as digits as its factorization.
213332333120999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 418000080.
The product of its (nonzero) digits is 4251528, while the sum is 53.
The spelling of 213332333120999 in words is "two hundred thirteen trillion, three hundred thirty-two billion, three hundred thirty-three million, one hundred twenty thousand, nine hundred ninety-nine".
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