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2133359844013 = 4745390634979
BaseRepresentation
bin11111000010110110001…
…001111101101010101101
321112221120111220212010001
4133002312021331222231
5234423110110002023
64312015121144301
7310062434322016
oct37026611755255
97487514825101
102133359844013
11752831019502
122a5561a8b091
13126237542188
147538027200d
153a760cb56ad
hex1f0b627daad

2133359844013 has 4 divisors (see below), whose sum is σ = 2178750479040. Its totient is φ = 2087969208988.

The previous prime is 2133359843999. The next prime is 2133359844043. The reversal of 2133359844013 is 3104489533312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2133359844013 - 217 = 2133359712941 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2133359844043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22695317443 + ... + 22695317536.

It is an arithmetic number, because the mean of its divisors is an integer number (544687619760).

Almost surely, 22133359844013 is an apocalyptic number.

It is an amenable number.

2133359844013 is a deficient number, since it is larger than the sum of its proper divisors (45390635027).

2133359844013 is an equidigital number, since it uses as much as digits as its factorization.

2133359844013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 45390635026.

The product of its (nonzero) digits is 933120, while the sum is 46.

The spelling of 2133359844013 in words is "two trillion, one hundred thirty-three billion, three hundred fifty-nine million, eight hundred forty-four thousand, thirteen".

Divisors: 1 47 45390634979 2133359844013