Base | Representation |
---|---|
bin | 11111000010111011100… |
… | …011011100100000001111 |
3 | 21112221210211100002021211 |
4 | 133002323203130200033 |
5 | 234423301301104444 |
6 | 4312032114235251 |
7 | 310064614162546 |
oct | 37027343344017 |
9 | 7487724302254 |
10 | 2133450409999 |
11 | 752878157027 |
12 | 2a5588285b27 |
13 | 12625023190c |
14 | 7538c2c915d |
15 | 3a768c04c34 |
hex | 1f0bb8dc80f |
2133450409999 has 4 divisors (see below), whose sum is σ = 2133889306120. Its totient is φ = 2133011513880.
The previous prime is 2133450409927. The next prime is 2133450410009. The reversal of 2133450409999 is 9999040543312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2133450409999 - 211 = 2133450407951 is a prime.
It is a super-2 number, since 2×21334504099992 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2133450409919) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219440769 + ... + 219450490.
It is an arithmetic number, because the mean of its divisors is an integer number (533472326530).
Almost surely, 22133450409999 is an apocalyptic number.
2133450409999 is a deficient number, since it is larger than the sum of its proper divisors (438896121).
2133450409999 is an equidigital number, since it uses as much as digits as its factorization.
2133450409999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 438896120.
The product of its (nonzero) digits is 9447840, while the sum is 58.
The spelling of 2133450409999 in words is "two trillion, one hundred thirty-three billion, four hundred fifty million, four hundred nine thousand, nine hundred ninety-nine".
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