Base | Representation |
---|---|
bin | 111111100110010… |
… | …1110001000011001 |
3 | 12111201120112001202 |
4 | 1333030232020121 |
5 | 13332303303423 |
6 | 551431523545 |
7 | 103612023131 |
oct | 17714561031 |
9 | 5451515052 |
10 | 2134041113 |
11 | 9a5679746 |
12 | 4b68295b5 |
13 | 280179329 |
14 | 1635cbac1 |
15 | c753d728 |
hex | 7f32e219 |
2134041113 has 2 divisors, whose sum is σ = 2134041114. Its totient is φ = 2134041112.
The previous prime is 2134041097. The next prime is 2134041139. The reversal of 2134041113 is 3111404312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1543939849 + 590101264 = 39293^2 + 24292^2 .
It is a cyclic number.
It is not a de Polignac number, because 2134041113 - 24 = 2134041097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (2134041313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067020556 + 1067020557.
It is an arithmetic number, because the mean of its divisors is an integer number (1067020557).
Almost surely, 22134041113 is an apocalyptic number.
It is an amenable number.
2134041113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2134041113 is an equidigital number, since it uses as much as digits as its factorization.
2134041113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
The square root of 2134041113 is about 46195.6828394169. The cubic root of 2134041113 is about 1287.4615290984.
Adding to 2134041113 its reverse (3111404312), we get a palindrome (5245445425).
The spelling of 2134041113 in words is "two billion, one hundred thirty-four million, forty-one thousand, one hundred thirteen".
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