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213412400000 = 27552323197
BaseRepresentation
bin1100011011000001011…
…1101100101110000000
3202101212002002012101222
43012300113230232000
511444032033300000
6242012412214212
721263362320002
oct3066027545600
9671762065358
10213412400000
11825648108a8
123543b46a368
1317180c84537
14a48751c372
155840bd8a85
hex31b05ecb80

213412400000 has 192 divisors, whose sum is σ = 554541694560. Its totient is φ = 81649920000.

The previous prime is 213412399999. The next prime is 213412400027. The reversal of 213412400000 is 4214312.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9188402 + ... + 9211598.

Almost surely, 2213412400000 is an apocalyptic number.

213412400000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 213412400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (277270847280).

213412400000 is an abundant number, since it is smaller than the sum of its proper divisors (341129294560).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

213412400000 is an frugal number, since it uses more digits than its factorization.

213412400000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23259 (or 23227 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 213412400000 its reverse (4214312), we get a palindrome (213416614312).

The spelling of 213412400000 in words is "two hundred thirteen billion, four hundred twelve million, four hundred thousand".