Base | Representation |
---|---|
bin | 11111000011101010100… |
… | …111111000000001010001 |
3 | 21120000211212021111220200 |
4 | 133003222213320001101 |
5 | 234431410431203213 |
6 | 4312242324125413 |
7 | 310123313350200 |
oct | 37035247700121 |
9 | 7500755244820 |
10 | 2134240100433 |
11 | 753142996151 |
12 | 2a5768836869 |
13 | 126347a1506c |
14 | 7542512d237 |
15 | 3a7b31e2273 |
hex | 1f0ea9f8051 |
2134240100433 has 36 divisors (see below), whose sum is σ = 3662404237440. Its totient is φ = 1193617552176.
The previous prime is 2134240100417. The next prime is 2134240100437. The reversal of 2134240100433 is 3340010424312.
2134240100433 is a `hidden beast` number, since 213 + 4 + 2 + 4 + 0 + 10 + 0 + 433 = 666.
It is not a de Polignac number, because 2134240100433 - 24 = 2134240100417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2134240100397 and 2134240100406.
It is not an unprimeable number, because it can be changed into a prime (2134240100437) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 51463813 + ... + 51505266.
It is an arithmetic number, because the mean of its divisors is an integer number (101733451040).
Almost surely, 22134240100433 is an apocalyptic number.
It is an amenable number.
2134240100433 is a deficient number, since it is larger than the sum of its proper divisors (1528164137007).
2134240100433 is a wasteful number, since it uses less digits than its factorization.
2134240100433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102969146 (or 102969136 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 2134240100433 its reverse (3340010424312), we get a palindrome (5474250524745).
The spelling of 2134240100433 in words is "two trillion, one hundred thirty-four billion, two hundred forty million, one hundred thousand, four hundred thirty-three".
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