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213424131433 = 6113127796419
BaseRepresentation
bin1100011011000100010…
…0011100110101101001
3202101212220011012220111
43012301010130311221
511444043034201213
6242013511454321
721263564120302
oct3066104346551
9671786135814
10213424131433
11825703a38a7
12354433873a1
1317183531206
14a488cd37a9
155841c54a3d
hex31b111cd69

213424131433 has 16 divisors (see below), whose sum is σ = 219370155840. Its totient is φ = 207568670400.

The previous prime is 213424131413. The next prime is 213424131451. The reversal of 213424131433 is 334131424312.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213424131433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213424131395 and 213424131404.

It is not an unprimeable number, because it can be changed into a prime (213424131413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2165298 + ... + 2261716.

It is an arithmetic number, because the mean of its divisors is an integer number (13710634740).

Almost surely, 2213424131433 is an apocalyptic number.

It is an amenable number.

213424131433 is a deficient number, since it is larger than the sum of its proper divisors (5946024407).

213424131433 is a wasteful number, since it uses less digits than its factorization.

213424131433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 96888.

The product of its digits is 20736, while the sum is 31.

Adding to 213424131433 its reverse (334131424312), we get a palindrome (547555555745).

The spelling of 213424131433 in words is "two hundred thirteen billion, four hundred twenty-four million, one hundred thirty-one thousand, four hundred thirty-three".

Divisors: 1 61 131 277 7991 16897 36287 96419 2213507 5881559 12630889 26708063 770484229 1629191843 3498756253 213424131433