Base | Representation |
---|---|
bin | 1100011011000100010… |
… | …0011100110101111011 |
3 | 202101212220011012221011 |
4 | 3012301010130311323 |
5 | 11444043034201301 |
6 | 242013511454351 |
7 | 21263564120326 |
oct | 3066104346573 |
9 | 671786135834 |
10 | 213424131451 |
11 | 825703a3913 |
12 | 354433873b7 |
13 | 1718353121b |
14 | a488cd37bd |
15 | 5841c54a51 |
hex | 31b111cd7b |
213424131451 has 2 divisors, whose sum is σ = 213424131452. Its totient is φ = 213424131450.
The previous prime is 213424131413. The next prime is 213424131497. The reversal of 213424131451 is 154131424312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213424131451 is a prime.
It is a super-2 number, since 2×2134241314512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (213424131251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106712065725 + 106712065726.
It is an arithmetic number, because the mean of its divisors is an integer number (106712065726).
Almost surely, 2213424131451 is an apocalyptic number.
213424131451 is a deficient number, since it is larger than the sum of its proper divisors (1).
213424131451 is an equidigital number, since it uses as much as digits as its factorization.
213424131451 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11520, while the sum is 31.
Adding to 213424131451 its reverse (154131424312), we get a palindrome (367555555763).
The spelling of 213424131451 in words is "two hundred thirteen billion, four hundred twenty-four million, one hundred thirty-one thousand, four hundred fifty-one".
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