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2134300444033 is a prime number
BaseRepresentation
bin11111000011101110001…
…110000100010110000001
321120001000001211021202211
4133003232032010112001
5234432021403202113
64312252321342121
7310124645305102
oct37035616042601
97501001737684
102134300444033
11753173a6119a
122a5784a97941
13126357382534
147542d15a3a9
153a7b8661b3d
hex1f0ee384581

2134300444033 has 2 divisors, whose sum is σ = 2134300444034. Its totient is φ = 2134300444032.

The previous prime is 2134300444013. The next prime is 2134300444039. The reversal of 2134300444033 is 3304440034312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1105763711809 + 1028536732224 = 1051553^2 + 1014168^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2134300444033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2134300443986 and 2134300444004.

It is not a weakly prime, because it can be changed into another prime (2134300444039) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1067150222016 + 1067150222017.

It is an arithmetic number, because the mean of its divisors is an integer number (1067150222017).

Almost surely, 22134300444033 is an apocalyptic number.

It is an amenable number.

2134300444033 is a deficient number, since it is larger than the sum of its proper divisors (1).

2134300444033 is an equidigital number, since it uses as much as digits as its factorization.

2134300444033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 31.

Adding to 2134300444033 its reverse (3304440034312), we get a palindrome (5438740478345).

The spelling of 2134300444033 in words is "two trillion, one hundred thirty-four billion, three hundred million, four hundred forty-four thousand, thirty-three".