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213433011011483 is a prime number
BaseRepresentation
bin110000100001110110111110…
…110011011111111110011011
31000222200222220111202002110122
4300201312332303133332123
5210433341301304331413
62033533434402503455
762646011660053214
oct6041667663377633
91028628814662418
10213433011011483
116200848258aa0a
121bb308b7664b8b
1392128536b9003
143a9c2da0c840b
1519a1d38265108
hexc21dbecdff9b

213433011011483 has 2 divisors, whose sum is σ = 213433011011484. Its totient is φ = 213433011011482.

The previous prime is 213433011011357. The next prime is 213433011011491. The reversal of 213433011011483 is 384110110334312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 213433011011483 - 234 = 213415831142299 is a prime.

It is not a weakly prime, because it can be changed into another prime (213433011011083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106716505505741 + 106716505505742.

It is an arithmetic number, because the mean of its divisors is an integer number (106716505505742).

Almost surely, 2213433011011483 is an apocalyptic number.

213433011011483 is a deficient number, since it is larger than the sum of its proper divisors (1).

213433011011483 is an equidigital number, since it uses as much as digits as its factorization.

213433011011483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 35.

Adding to 213433011011483 its reverse (384110110334312), we get a palindrome (597543121345795).

The spelling of 213433011011483 in words is "two hundred thirteen trillion, four hundred thirty-three billion, eleven million, eleven thousand, four hundred eighty-three".