Base | Representation |
---|---|
bin | 110000100001110111001100… |
… | …011101011110111101001001 |
3 | 1000222201000111110212001212021 |
4 | 300201313030131132331021 |
5 | 210433342233432334121 |
6 | 2033533513225244441 |
7 | 62646020441340364 |
oct | 6041671435367511 |
9 | 1028630443761767 |
10 | 213433240121161 |
11 | 6200858a945455 |
12 | 1bb30960333721 |
13 | 921288bcc5c78 |
14 | 3a9c31c6c70db |
15 | 19a1d4d41e641 |
hex | c21dcc75ef49 |
213433240121161 has 8 divisors (see below), whose sum is σ = 218052817236864. Its totient is φ = 208835608740720.
The previous prime is 213433240121137. The next prime is 213433240121219. The reversal of 213433240121161 is 161121042334312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 213433240121161 - 245 = 178248868032329 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (213433240124161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5486414155 + ... + 5486453056.
It is an arithmetic number, because the mean of its divisors is an integer number (27256602154608).
Almost surely, 2213433240121161 is an apocalyptic number.
It is an amenable number.
213433240121161 is a deficient number, since it is larger than the sum of its proper divisors (4619577115703).
213433240121161 is a wasteful number, since it uses less digits than its factorization.
213433240121161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10972867631.
The product of its (nonzero) digits is 20736, while the sum is 34.
Adding to 213433240121161 its reverse (161121042334312), we get a palindrome (374554282455473).
The spelling of 213433240121161 in words is "two hundred thirteen trillion, four hundred thirty-three billion, two hundred forty million, one hundred twenty-one thousand, one hundred sixty-one".
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