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213433325212753 is a prime number
BaseRepresentation
bin110000100001110111010001…
…100010000101010001010001
31000222201000201101222011120201
4300201313101202011101101
5210433342422223302003
62033533525505135201
762646022523531002
oct6041672142052121
91028630641864521
10213433325212753
1162008623983a88
121bb3098492a501
1392128a3819a19
143a9c329b171a9
1519a1d55b2bb1d
hexc21dd1885451

213433325212753 has 2 divisors, whose sum is σ = 213433325212754. Its totient is φ = 213433325212752.

The previous prime is 213433325212729. The next prime is 213433325212769. The reversal of 213433325212753 is 357212523334312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 163443235698064 + 49990089514689 = 12784492^2 + 7070367^2 .

It is a cyclic number.

It is not a de Polignac number, because 213433325212753 - 221 = 213433323115601 is a prime.

It is a super-2 number, since 2×2134333252127532 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213433325212253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106716662606376 + 106716662606377.

It is an arithmetic number, because the mean of its divisors is an integer number (106716662606377).

Almost surely, 2213433325212753 is an apocalyptic number.

It is an amenable number.

213433325212753 is a deficient number, since it is larger than the sum of its proper divisors (1).

213433325212753 is an equidigital number, since it uses as much as digits as its factorization.

213433325212753 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2721600, while the sum is 46.

The spelling of 213433325212753 in words is "two hundred thirteen trillion, four hundred thirty-three billion, three hundred twenty-five million, two hundred twelve thousand, seven hundred fifty-three".