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213440200255 = 543499815599
BaseRepresentation
bin1100011011001000000…
…1101111111000111111
3202101221000101121012001
43012302001233320333
511444111142402010
6242015244123131
721264150524212
oct3066201577077
9671830347161
10213440200255
1182579479617
12354488364a7
13171869691a9
14a48b0b7779
15584337ac3a
hex31b206fe3f

213440200255 has 8 divisors (see below), whose sum is σ = 256187160000. Its totient is φ = 170712880416.

The previous prime is 213440200223. The next prime is 213440200313. The reversal of 213440200255 is 552002044312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213440200255 - 25 = 213440200223 is a prime.

It is a super-3 number, since 3×2134402002553 (a number of 35 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4886055 + ... + 4929544.

It is an arithmetic number, because the mean of its divisors is an integer number (32023395000).

Almost surely, 2213440200255 is an apocalyptic number.

213440200255 is a deficient number, since it is larger than the sum of its proper divisors (42746959745).

213440200255 is an equidigital number, since it uses as much as digits as its factorization.

213440200255 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9819953.

The product of its (nonzero) digits is 9600, while the sum is 28.

Adding to 213440200255 its reverse (552002044312), we get a palindrome (765442244567).

The spelling of 213440200255 in words is "two hundred thirteen billion, four hundred forty million, two hundred thousand, two hundred fifty-five".

Divisors: 1 5 4349 21745 9815599 49077995 42688040051 213440200255