Base | Representation |
---|---|
bin | 100111110000011001… |
… | …111100110001110011 |
3 | 11002012000002010020102 |
4 | 213300121330301303 |
5 | 1144411114240201 |
6 | 31335520503015 |
7 | 3040564232156 |
oct | 476031746163 |
9 | 132160063212 |
10 | 42688040051 |
11 | 17116316348 |
12 | 833417aa6b |
13 | 4043c3c2c7 |
14 | 20cd5a9c9d |
15 | 119c9a826b |
hex | 9f067cc73 |
42688040051 has 4 divisors (see below), whose sum is σ = 42697860000. Its totient is φ = 42678220104.
The previous prime is 42688040033. The next prime is 42688040093. The reversal of 42688040051 is 15004088624.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 42688040051 - 234 = 25508170867 is a prime.
It is a super-3 number, since 3×426880400513 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 42688039987 and 42688040014.
It is not an unprimeable number, because it can be changed into a prime (42688040951) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4903451 + ... + 4912148.
It is an arithmetic number, because the mean of its divisors is an integer number (10674465000).
Almost surely, 242688040051 is an apocalyptic number.
42688040051 is a deficient number, since it is larger than the sum of its proper divisors (9819949).
42688040051 is an equidigital number, since it uses as much as digits as its factorization.
42688040051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9819948.
The product of its (nonzero) digits is 61440, while the sum is 38.
The spelling of 42688040051 in words is "forty-two billion, six hundred eighty-eight million, forty thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •