Base | Representation |
---|---|
bin | 110000100010000000011110… |
… | …010111001101010011100011 |
3 | 1000222201222012212220210021111 |
4 | 300202000132113031103203 |
5 | 210434023140230023212 |
6 | 2033542242045004151 |
7 | 62646522401202616 |
oct | 6042003627152343 |
9 | 1028658185823244 |
10 | 213443204142307 |
11 | 62011833315a77 |
12 | 1bb32881253657 |
13 | 92137b93c6c79 |
14 | 3a9c9c5b6217d |
15 | 19a2233071ea7 |
hex | c2201e5cd4e3 |
213443204142307 has 2 divisors, whose sum is σ = 213443204142308. Its totient is φ = 213443204142306.
The previous prime is 213443204142299. The next prime is 213443204142323. The reversal of 213443204142307 is 703241402344312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213443204142307 - 23 = 213443204142299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 213443204142307.
It is not a weakly prime, because it can be changed into another prime (213443204142347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106721602071153 + 106721602071154.
It is an arithmetic number, because the mean of its divisors is an integer number (106721602071154).
Almost surely, 2213443204142307 is an apocalyptic number.
213443204142307 is a deficient number, since it is larger than the sum of its proper divisors (1).
213443204142307 is an equidigital number, since it uses as much as digits as its factorization.
213443204142307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 40.
Adding to 213443204142307 its reverse (703241402344312), we get a palindrome (916684606486619).
The spelling of 213443204142307 in words is "two hundred thirteen trillion, four hundred forty-three billion, two hundred four million, one hundred forty-two thousand, three hundred seven".
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