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213450401415 = 3514230026761
BaseRepresentation
bin1100011011001010100…
…0101010011010000111
3202101221201120212112210
43012302220222122013
511444121300321130
6242020250514503
721264333322206
oct3066250523207
9671851525483
10213450401415
1182584206929
1235450135a33
1317188acb494
14a48c5b123d
1558441e35b0
hex31b2a2a687

213450401415 has 8 divisors (see below), whose sum is σ = 341520642288. Its totient is φ = 113840214080.

The previous prime is 213450401393. The next prime is 213450401431. The reversal of 213450401415 is 514104054312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 213450401415 - 27 = 213450401287 is a prime.

It is a super-2 number, since 2×2134504014152 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7115013366 + ... + 7115013395.

It is an arithmetic number, because the mean of its divisors is an integer number (42690080286).

Almost surely, 2213450401415 is an apocalyptic number.

213450401415 is a deficient number, since it is larger than the sum of its proper divisors (128070240873).

213450401415 is a wasteful number, since it uses less digits than its factorization.

213450401415 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14230026769.

The product of its (nonzero) digits is 9600, while the sum is 30.

Adding to 213450401415 its reverse (514104054312), we get a palindrome (727554455727).

The spelling of 213450401415 in words is "two hundred thirteen billion, four hundred fifty million, four hundred one thousand, four hundred fifteen".

Divisors: 1 3 5 15 14230026761 42690080283 71150133805 213450401415