Base | Representation |
---|---|
bin | 10011111000010001… |
… | …111100110001010001 |
3 | 2001002120222210222202 |
4 | 103320101330301101 |
5 | 322203400332423 |
6 | 13450024212545 |
7 | 1353646155431 |
oct | 237021746121 |
9 | 61076883882 |
10 | 21345324113 |
11 | 9063973a33 |
12 | 417860a155 |
13 | 20223218c9 |
14 | 1066c442c1 |
15 | 84de10728 |
hex | 4f847cc51 |
21345324113 has 2 divisors, whose sum is σ = 21345324114. Its totient is φ = 21345324112.
The previous prime is 21345324097. The next prime is 21345324139. The reversal of 21345324113 is 31142354312.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18000783889 + 3344540224 = 134167^2 + 57832^2 .
It is a cyclic number.
It is not a de Polignac number, because 21345324113 - 24 = 21345324097 is a prime.
It is a super-2 number, since 2×213453241132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21345324193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10672662056 + 10672662057.
It is an arithmetic number, because the mean of its divisors is an integer number (10672662057).
Almost surely, 221345324113 is an apocalyptic number.
It is an amenable number.
21345324113 is a deficient number, since it is larger than the sum of its proper divisors (1).
21345324113 is an equidigital number, since it uses as much as digits as its factorization.
21345324113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 29.
Adding to 21345324113 its reverse (31142354312), we get a palindrome (52487678425).
The spelling of 21345324113 in words is "twenty-one billion, three hundred forty-five million, three hundred twenty-four thousand, one hundred thirteen".
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