Base | Representation |
---|---|
bin | 1001101101010001111001… |
… | …00101110110100010011111 |
3 | 2210120202100102011102011222 |
4 | 10312220330211312202133 |
5 | 10244222131012014144 |
6 | 113222402301003555 |
7 | 4332161442163166 |
oct | 466507445664237 |
9 | 83522312142158 |
10 | 21347004016799 |
11 | 68902392857aa |
12 | 24892385535bb |
13 | bbb024541a66 |
14 | 53b2b42983dd |
15 | 2704406022ee |
hex | 136a3c97689f |
21347004016799 has 4 divisors (see below), whose sum is σ = 21347033919960. Its totient is φ = 21346974113640.
The previous prime is 21347004016787. The next prime is 21347004016847. The reversal of 21347004016799 is 99761040074312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21347004016799 - 24 = 21347004016783 is a prime.
It is a super-3 number, since 3×213470040167993 (a number of 41 digits) contains 333 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 21347004016799.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21347004046799) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13853912 + ... + 15317469.
It is an arithmetic number, because the mean of its divisors is an integer number (5336758479990).
Almost surely, 221347004016799 is an apocalyptic number.
21347004016799 is a deficient number, since it is larger than the sum of its proper divisors (29903161).
21347004016799 is an equidigital number, since it uses as much as digits as its factorization.
21347004016799 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29903160.
The product of its (nonzero) digits is 2286144, while the sum is 53.
The spelling of 21347004016799 in words is "twenty-one trillion, three hundred forty-seven billion, four million, sixteen thousand, seven hundred ninety-nine".
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