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21356043481 is a prime number
BaseRepresentation
bin10011111000111010…
…110101110011011001
32001010100011102012101
4103320322311303121
5322214121342411
613451050043401
71354136242303
oct237072656331
961110142171
1021356043481
119069a25613
124180119561
132024605a26
141068434973
1584ed2b8c1
hex4f8eb5cd9

21356043481 has 2 divisors, whose sum is σ = 21356043482. Its totient is φ = 21356043480.

The previous prime is 21356043413. The next prime is 21356043547. The reversal of 21356043481 is 18434065312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21058653456 + 297390025 = 145116^2 + 17245^2 .

It is a cyclic number.

It is not a de Polignac number, because 21356043481 - 219 = 21355519193 is a prime.

It is a super-2 number, since 2×213560434812 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 21356043481.

It is not a weakly prime, because it can be changed into another prime (21356043281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10678021740 + 10678021741.

It is an arithmetic number, because the mean of its divisors is an integer number (10678021741).

Almost surely, 221356043481 is an apocalyptic number.

It is an amenable number.

21356043481 is a deficient number, since it is larger than the sum of its proper divisors (1).

21356043481 is an equidigital number, since it uses as much as digits as its factorization.

21356043481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 37.

The spelling of 21356043481 in words is "twenty-one billion, three hundred fifty-six million, forty-three thousand, four hundred eighty-one".