Base | Representation |
---|---|
bin | 1001101101110011100000… |
… | …10111011110111010000011 |
3 | 2210122110221020122002211221 |
4 | 10312321300113132322003 |
5 | 10300021111422100103 |
6 | 113234545235215511 |
7 | 4333400630100064 |
oct | 466716027367203 |
9 | 83573836562757 |
10 | 21365052534403 |
11 | 6897960196156 |
12 | 2490834a47597 |
13 | bbc93c82ba86 |
14 | 53c10731456b |
15 | 270b49d911bd |
hex | 136e705dee83 |
21365052534403 has 2 divisors, whose sum is σ = 21365052534404. Its totient is φ = 21365052534402.
The previous prime is 21365052534383. The next prime is 21365052534443. The reversal of 21365052534403 is 30443525056312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21365052534403 - 225 = 21365018979971 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21365052534403.
It is not a weakly prime, because it can be changed into another prime (21365052534443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10682526267201 + 10682526267202.
It is an arithmetic number, because the mean of its divisors is an integer number (10682526267202).
Almost surely, 221365052534403 is an apocalyptic number.
21365052534403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21365052534403 is an equidigital number, since it uses as much as digits as its factorization.
21365052534403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296000, while the sum is 43.
The spelling of 21365052534403 in words is "twenty-one trillion, three hundred sixty-five billion, fifty-two million, five hundred thirty-four thousand, four hundred three".
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