Base | Representation |
---|---|
bin | 1001101101110100011101… |
… | …01000010110110011100011 |
3 | 2210122112020122000221211122 |
4 | 10312322032220112303203 |
5 | 10300023131412233042 |
6 | 113235111454002455 |
7 | 4333416333600635 |
oct | 466721650266343 |
9 | 83575218027748 |
10 | 21365560274147 |
11 | 68980a0859581 |
12 | 2490956aa642b |
13 | bbc9c0a939ab |
14 | 53c154922a55 |
15 | 270b797377d2 |
hex | 136e8ea16ce3 |
21365560274147 has 4 divisors (see below), whose sum is σ = 21426085941000. Its totient is φ = 21305034607296.
The previous prime is 21365560274119. The next prime is 21365560274173. The reversal of 21365560274147 is 74147206556312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21365560274147 - 28 = 21365560273891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (21365560274647) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30262832897 + ... + 30262833602.
It is an arithmetic number, because the mean of its divisors is an integer number (5356521485250).
Almost surely, 221365560274147 is an apocalyptic number.
21365560274147 is a deficient number, since it is larger than the sum of its proper divisors (60525666853).
21365560274147 is an equidigital number, since it uses as much as digits as its factorization.
21365560274147 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60525666852.
The product of its (nonzero) digits is 8467200, while the sum is 53.
The spelling of 21365560274147 in words is "twenty-one trillion, three hundred sixty-five billion, five hundred sixty million, two hundred seventy-four thousand, one hundred forty-seven".
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