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213799184393 is a prime number
BaseRepresentation
bin1100011100011101101…
…1001010100000001001
3202102212000212212211212
43013013123022200021
512000330042400033
6242115030302505
721306100040204
oct3070733124011
9672760785755
10213799184393
118274307a723
1235528ab7a35
1317213149742
14a4c2a4293b
155864b3b748
hex31c76ca809

213799184393 has 2 divisors, whose sum is σ = 213799184394. Its totient is φ = 213799184392.

The previous prime is 213799184381. The next prime is 213799184419. The reversal of 213799184393 is 393481997312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 212929642249 + 869542144 = 461443^2 + 29488^2 .

It is a cyclic number.

It is not a de Polignac number, because 213799184393 - 212 = 213799180297 is a prime.

It is a super-2 number, since 2×2137991843932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (213799184323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106899592196 + 106899592197.

It is an arithmetic number, because the mean of its divisors is an integer number (106899592197).

Almost surely, 2213799184393 is an apocalyptic number.

It is an amenable number.

213799184393 is a deficient number, since it is larger than the sum of its proper divisors (1).

213799184393 is an equidigital number, since it uses as much as digits as its factorization.

213799184393 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8817984, while the sum is 59.

The spelling of 213799184393 in words is "two hundred thirteen billion, seven hundred ninety-nine million, one hundred eighty-four thousand, three hundred ninety-three".