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2138711040 = 210375191
BaseRepresentation
bin111111101111010…
…0010010000000000
312112001100210000000
41333132202100000
513340002223130
6552120000000
7103666513104
oct17736422000
95461323000
102138711040
119a8279294
124b8300000
13281122abb
14164085904
15c7b62260
hex7f7a2400

2138711040 has 352 divisors, whose sum is σ = 7734712320. Its totient is φ = 567336960.

The previous prime is 2138711039. The next prime is 2138711093. The reversal of 2138711040 is 401178312.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 2138710995 and 2138711013.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11197345 + ... + 11197535.

Almost surely, 22138711040 is an apocalyptic number.

2138711040 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2138711040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3867356160).

2138711040 is an abundant number, since it is smaller than the sum of its proper divisors (5596001280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2138711040 is an frugal number, since it uses more digits than its factorization.

2138711040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 237 (or 201 counting only the distinct ones).

The product of its (nonzero) digits is 1344, while the sum is 27.

The square root of 2138711040 is about 46246.2002763470. The cubic root of 2138711040 is about 1288.3999632316.

Adding to 2138711040 its reverse (401178312), we get a palindrome (2539889352).

The spelling of 2138711040 in words is "two billion, one hundred thirty-eight million, seven hundred eleven thousand, forty".