Base | Representation |
---|---|
bin | 11111000111111011111… |
… | …000001100100010110111 |
3 | 21120110200100202010111002 |
4 | 133013323320030202313 |
5 | 240020303041340100 |
6 | 4314321253033515 |
7 | 310345031533022 |
oct | 37077370144267 |
9 | 7513610663432 |
10 | 2138824558775 |
11 | 7550857825a3 |
12 | 2a662802589b |
13 | 1268c87502c8 |
14 | 7573bd421b9 |
15 | 3a9809152d5 |
hex | 1f1fbe0c8b7 |
2138824558775 has 12 divisors (see below), whose sum is σ = 2652887756400. Its totient is φ = 1710578806080.
The previous prime is 2138824558769. The next prime is 2138824558781. The reversal of 2138824558775 is 5778554288312.
It is an interprime number because it is at equal distance from previous prime (2138824558769) and next prime (2138824558781).
It is a de Polignac number, because none of the positive numbers 2k-2138824558775 is a prime.
It is a hoax number, since the sum of its digits (65) coincides with the sum of the digits of its distinct prime factors.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11930270 + ... + 12108219.
It is an arithmetic number, because the mean of its divisors is an integer number (221073979700).
Almost surely, 22138824558775 is an apocalyptic number.
2138824558775 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2138824558775 is a deficient number, since it is larger than the sum of its proper divisors (514063197625).
2138824558775 is a wasteful number, since it uses less digits than its factorization.
2138824558775 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24042058 (or 24042053 counting only the distinct ones).
The product of its digits is 150528000, while the sum is 65.
The spelling of 2138824558775 in words is "two trillion, one hundred thirty-eight billion, eight hundred twenty-four million, five hundred fifty-eight thousand, seven hundred seventy-five".
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