Base | Representation |
---|---|
bin | 11111001001000010001… |
… | …011100001101101001111 |
3 | 21120120201120010112122002 |
4 | 133021002023201231033 |
5 | 240030212013000221 |
6 | 4315034305142515 |
7 | 310416203064326 |
oct | 37110213415517 |
9 | 7516646115562 |
10 | 2140004031311 |
11 | 755630538793 |
12 | 2a68b702aa3b |
13 | 126a55c08253 |
14 | 7581084b0bd |
15 | 3a9ee24880b |
hex | 1f2422e1b4f |
2140004031311 has 4 divisors (see below), whose sum is σ = 2213797273800. Its totient is φ = 2066210788824.
The previous prime is 2140004031307. The next prime is 2140004031331. The reversal of 2140004031311 is 1131304000412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2140004031311 - 22 = 2140004031307 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2140004031331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36896621201 + ... + 36896621258.
It is an arithmetic number, because the mean of its divisors is an integer number (553449318450).
Almost surely, 22140004031311 is an apocalyptic number.
2140004031311 is a deficient number, since it is larger than the sum of its proper divisors (73793242489).
2140004031311 is an equidigital number, since it uses as much as digits as its factorization.
2140004031311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73793242488.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 2140004031311 its reverse (1131304000412), we get a palindrome (3271308031723).
The spelling of 2140004031311 in words is "two trillion, one hundred forty billion, four million, thirty-one thousand, three hundred eleven".
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