Base | Representation |
---|---|
bin | 11111001001000010001… |
… | …011100001101101010000 |
3 | 21120120201120010112122010 |
4 | 133021002023201231100 |
5 | 240030212013000222 |
6 | 4315034305142520 |
7 | 310416203064330 |
oct | 37110213415520 |
9 | 7516646115563 |
10 | 2140004031312 |
11 | 755630538794 |
12 | 2a68b702aa40 |
13 | 126a55c08254 |
14 | 7581084b0c0 |
15 | 3a9ee24880c |
hex | 1f2422e1b50 |
2140004031312 has 80 divisors (see below), whose sum is σ = 6425193761280. Its totient is φ = 601066502016.
The previous prime is 2140004031307. The next prime is 2140004031331. The reversal of 2140004031312 is 2131304000412.
It is a super-2 number, since 2×21400040313122 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 53955258 + ... + 53994905.
It is an arithmetic number, because the mean of its divisors is an integer number (80314922016).
Almost surely, 22140004031312 is an apocalyptic number.
It is an amenable number.
2140004031312 is an abundant number, since it is smaller than the sum of its proper divisors (4285189729968).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2140004031312 is a wasteful number, since it uses less digits than its factorization.
2140004031312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107950240 (or 107950234 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 2140004031312 its reverse (2131304000412), we get a palindrome (4271308031724).
The spelling of 2140004031312 in words is "two trillion, one hundred forty billion, four million, thirty-one thousand, three hundred twelve".
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