Base | Representation |
---|---|
bin | 11111001001000010001… |
… | …011100001101110101001 |
3 | 21120120201120010112202102 |
4 | 133021002023201232221 |
5 | 240030212013001101 |
6 | 4315034305143145 |
7 | 310416203064515 |
oct | 37110213415651 |
9 | 7516646115672 |
10 | 2140004031401 |
11 | 755630538865 |
12 | 2a68b702aab5 |
13 | 126a55c082c2 |
14 | 7581084b145 |
15 | 3a9ee24886b |
hex | 1f2422e1ba9 |
2140004031401 has 2 divisors, whose sum is σ = 2140004031402. Its totient is φ = 2140004031400.
The previous prime is 2140004031331. The next prime is 2140004031409. The reversal of 2140004031401 is 1041304000412.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2128447566400 + 11556465001 = 1458920^2 + 107501^2 .
It is a cyclic number.
It is not a de Polignac number, because 2140004031401 - 218 = 2140003769257 is a prime.
It is not a weakly prime, because it can be changed into another prime (2140004031409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070002015700 + 1070002015701.
It is an arithmetic number, because the mean of its divisors is an integer number (1070002015701).
Almost surely, 22140004031401 is an apocalyptic number.
It is an amenable number.
2140004031401 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140004031401 is an equidigital number, since it uses as much as digits as its factorization.
2140004031401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 2140004031401 its reverse (1041304000412), we get a palindrome (3181308031813).
The spelling of 2140004031401 in words is "two trillion, one hundred forty billion, four million, thirty-one thousand, four hundred one".
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