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2140004031401 is a prime number
BaseRepresentation
bin11111001001000010001…
…011100001101110101001
321120120201120010112202102
4133021002023201232221
5240030212013001101
64315034305143145
7310416203064515
oct37110213415651
97516646115672
102140004031401
11755630538865
122a68b702aab5
13126a55c082c2
147581084b145
153a9ee24886b
hex1f2422e1ba9

2140004031401 has 2 divisors, whose sum is σ = 2140004031402. Its totient is φ = 2140004031400.

The previous prime is 2140004031331. The next prime is 2140004031409. The reversal of 2140004031401 is 1041304000412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2128447566400 + 11556465001 = 1458920^2 + 107501^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140004031401 - 218 = 2140003769257 is a prime.

It is not a weakly prime, because it can be changed into another prime (2140004031409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070002015700 + 1070002015701.

It is an arithmetic number, because the mean of its divisors is an integer number (1070002015701).

Almost surely, 22140004031401 is an apocalyptic number.

It is an amenable number.

2140004031401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140004031401 is an equidigital number, since it uses as much as digits as its factorization.

2140004031401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 2140004031401 its reverse (1041304000412), we get a palindrome (3181308031813).

The spelling of 2140004031401 in words is "two trillion, one hundred forty billion, four million, thirty-one thousand, four hundred one".