Base | Representation |
---|---|
bin | 11111001001000010100… |
… | …011110111010110010101 |
3 | 21120120202000010200111011 |
4 | 133021002203313112111 |
5 | 240030220131131123 |
6 | 4315035054012221 |
7 | 310416311236240 |
oct | 37110243672625 |
9 | 7516660120434 |
10 | 2140010411413 |
11 | 7556340a61a6 |
12 | 2a68b91a7071 |
13 | 126a57330264 |
14 | 7581162c257 |
15 | 3a9eeaa8e0d |
hex | 1f2428f7595 |
2140010411413 has 32 divisors (see below), whose sum is σ = 2558859724800. Its totient is φ = 1749873935040.
The previous prime is 2140010411401. The next prime is 2140010411417. The reversal of 2140010411413 is 3141140100412.
It is not a de Polignac number, because 2140010411413 - 221 = 2140008314261 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2140010411417) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 141256563 + ... + 141271711.
It is an arithmetic number, because the mean of its divisors is an integer number (79964366400).
Almost surely, 22140010411413 is an apocalyptic number.
2140010411413 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
2140010411413 is a deficient number, since it is larger than the sum of its proper divisors (418849313387).
2140010411413 is a wasteful number, since it uses less digits than its factorization.
2140010411413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17457.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 2140010411413 its reverse (3141140100412), we get a palindrome (5281150511825).
The spelling of 2140010411413 in words is "two trillion, one hundred forty billion, ten million, four hundred eleven thousand, four hundred thirteen".
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