Base | Representation |
---|---|
bin | 1100011101010000010… |
… | …0011111000101010011 |
3 | 202110101211002122222222 |
4 | 3013110010133011103 |
5 | 12001243400440222 |
6 | 242152045451255 |
7 | 21314254255025 |
oct | 3072404370523 |
9 | 673354078888 |
10 | 214011343187 |
11 | 82841907774 |
12 | 35587b70b2b |
13 | 172480a00a5 |
14 | a502cac015 |
15 | 5878598542 |
hex | 31d411f153 |
214011343187 has 2 divisors, whose sum is σ = 214011343188. Its totient is φ = 214011343186.
The previous prime is 214011343093. The next prime is 214011343201. The reversal of 214011343187 is 781343110412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 214011343187 - 218 = 214011081043 is a prime.
It is not a weakly prime, because it can be changed into another prime (214011342187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107005671593 + 107005671594.
It is an arithmetic number, because the mean of its divisors is an integer number (107005671594).
Almost surely, 2214011343187 is an apocalyptic number.
214011343187 is a deficient number, since it is larger than the sum of its proper divisors (1).
214011343187 is an equidigital number, since it uses as much as digits as its factorization.
214011343187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 35.
Adding to 214011343187 its reverse (781343110412), we get a palindrome (995354453599).
The spelling of 214011343187 in words is "two hundred fourteen billion, eleven million, three hundred forty-three thousand, one hundred eighty-seven".
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