214013112343 has 4 divisors (see below), whose sum is σ = 214116552360. Its totient is φ = 213909672328.

The previous prime is 214013112317. The next prime is 214013112347. The reversal of 214013112343 is 343211310412.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-214013112343 is a prime.

It is a super-2 number, since 2×214013112343² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214013112347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51716905 + ... + 51721042.

It is an arithmetic number, because the mean of its divisors is an integer number (53529138090).

Almost surely, 2^214013112343 is an apocalyptic number.

214013112343 is a deficient number, since it is larger than the sum of its proper divisors (103440017).

214013112343 is a wasteful number, since it uses less digits than its factorization.

214013112343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103440016.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 214013112343 its reverse (343211310412), we get a palindrome (557224422755).

The spelling of 214013112343 in words is "two hundred fourteen billion, thirteen million, one hundred twelve thousand, three hundred forty-three".