Base | Representation |
---|---|
bin | 110000101010010011010111… |
… | …001101010010101101100100 |
3 | 1001001202110120201212001210101 |
4 | 300222103113031102231210 |
5 | 211022343104144323134 |
6 | 2035100154201233444 |
7 | 63035642422506046 |
oct | 6052232715225544 |
9 | 1031673521761711 |
10 | 214013241011044 |
11 | 62211562267572 |
12 | 20005249492884 |
13 | 92554924ca8b7 |
14 | 3abc420837a96 |
15 | 19b1e97649e14 |
hex | c2a4d7352b64 |
214013241011044 has 48 divisors (see below), whose sum is σ = 382422985781760. Its totient is φ = 104771066906880.
The previous prime is 214013241011041. The next prime is 214013241011111. The reversal of 214013241011044 is 440110142310412.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (214013241011041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 415891629 + ... + 416405899.
It is an arithmetic number, because the mean of its divisors is an integer number (7967145537120).
Almost surely, 2214013241011044 is an apocalyptic number.
It is an amenable number.
214013241011044 is a deficient number, since it is larger than the sum of its proper divisors (168409744770716).
214013241011044 is a wasteful number, since it uses less digits than its factorization.
214013241011044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 524740 (or 524738 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 28.
Adding to 214013241011044 its reverse (440110142310412), we get a palindrome (654123383321456).
The spelling of 214013241011044 in words is "two hundred fourteen trillion, thirteen billion, two hundred forty-one million, eleven thousand, forty-four".
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