Base | Representation |
---|---|
bin | 10011111011100111… |
… | …100100101111011011 |
3 | 2001020111100221002102 |
4 | 103323213210233123 |
5 | 322312214341012 |
6 | 13455344354015 |
7 | 1355226154043 |
oct | 237347445733 |
9 | 61214327072 |
10 | 21401324507 |
11 | 9092542952 |
12 | 419331590b |
13 | 2030acb234 |
14 | 1070460723 |
15 | 853cc32c2 |
hex | 4fb9e4bdb |
21401324507 has 2 divisors, whose sum is σ = 21401324508. Its totient is φ = 21401324506.
The previous prime is 21401324479. The next prime is 21401324513. The reversal of 21401324507 is 70542310412.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21401324507 - 28 = 21401324251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21401324507.
It is not a weakly prime, because it can be changed into another prime (21401324587) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10700662253 + 10700662254.
It is an arithmetic number, because the mean of its divisors is an integer number (10700662254).
Almost surely, 221401324507 is an apocalyptic number.
21401324507 is a deficient number, since it is larger than the sum of its proper divisors (1).
21401324507 is an equidigital number, since it uses as much as digits as its factorization.
21401324507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 21401324507 its reverse (70542310412), we get a palindrome (91943634919).
The spelling of 21401324507 in words is "twenty-one billion, four hundred one million, three hundred twenty-four thousand, five hundred seven".
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