2140204432021 has 4 divisors (see below), whose sum is σ = 2140280035200. Its totient is φ = 2140128828844.

The previous prime is 2140204432019. The next prime is 2140204432033. The reversal of 2140204432021 is 1202344020412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2140204432021 - 2¹ = 2140204432019 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2140204432081) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37759111 + ... + 37815748.

It is an arithmetic number, because the mean of its divisors is an integer number (535070008800).

Almost surely, 2^{2140204432021} is an apocalyptic number.

It is an amenable number.

2140204432021 is a deficient number, since it is larger than the sum of its proper divisors (75603179).

2140204432021 is an equidigital number, since it uses as much as digits as its factorization.

2140204432021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75603178.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 2140204432021 its reverse (1202344020412), we get a palindrome (3342548452433).

The spelling of 2140204432021 in words is "two trillion, one hundred forty billion, two hundred four million, four hundred thirty-two thousand, twenty-one".