Base | Representation |
---|---|
bin | 11111001001001111011… |
… | …100000000001010110001 |
3 | 21120121022001122210110121 |
4 | 133021033130000022301 |
5 | 240031140433013233 |
6 | 4315112332330241 |
7 | 310424543461462 |
oct | 37111734001261 |
9 | 7517261583417 |
10 | 2140226454193 |
11 | 755735046353 |
12 | 2a6959613981 |
13 | 126a90013719 |
14 | 758321c8d69 |
15 | 3aa13a3192d |
hex | 1f24f7002b1 |
2140226454193 has 2 divisors, whose sum is σ = 2140226454194. Its totient is φ = 2140226454192.
The previous prime is 2140226454187. The next prime is 2140226454227. The reversal of 2140226454193 is 3914546220412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2138578662544 + 1647791649 = 1462388^2 + 40593^2 .
It is a cyclic number.
It is not a de Polignac number, because 2140226454193 - 217 = 2140226323121 is a prime.
It is not a weakly prime, because it can be changed into another prime (2140226454133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070113227096 + 1070113227097.
It is an arithmetic number, because the mean of its divisors is an integer number (1070113227097).
Almost surely, 22140226454193 is an apocalyptic number.
It is an amenable number.
2140226454193 is a deficient number, since it is larger than the sum of its proper divisors (1).
2140226454193 is an equidigital number, since it uses as much as digits as its factorization.
2140226454193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 414720, while the sum is 43.
The spelling of 2140226454193 in words is "two trillion, one hundred forty billion, two hundred twenty-six million, four hundred fifty-four thousand, one hundred ninety-three".
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