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2140251345019 is a prime number
BaseRepresentation
bin11111001001010000111…
…010111101000001111011
321120121100210111101021001
4133021100322331001323
5240031213321020034
64315115022025431
7310425265160464
oct37112072750173
97517323441231
102140251345019
117557480a7187
122a6965a18277
13126a9521a018
1475835627d6b
153aa15ceba14
hex1f250ebd07b

2140251345019 has 2 divisors, whose sum is σ = 2140251345020. Its totient is φ = 2140251345018.

The previous prime is 2140251344971. The next prime is 2140251345091. The reversal of 2140251345019 is 9105431520412.

Together with next prime (2140251345091) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2140251345019 - 29 = 2140251344507 is a prime.

It is a super-2 number, since 2×21402513450192 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2140251315019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070125672509 + 1070125672510.

It is an arithmetic number, because the mean of its divisors is an integer number (1070125672510).

Almost surely, 22140251345019 is an apocalyptic number.

2140251345019 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140251345019 is an equidigital number, since it uses as much as digits as its factorization.

2140251345019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 2140251345019 in words is "two trillion, one hundred forty billion, two hundred fifty-one million, three hundred forty-five thousand, nineteen".