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214031321131 is a prime number
BaseRepresentation
bin1100011101010101000…
…0101100100000101011
3202110110012200122120211
43013111100230200223
512001314004234011
6242154042001551
721314616132535
oct3072520544053
9673405618524
10214031321131
1182852112471
12355927a62b7
131724c276464
14a5057cc855
15587a1e2b21
hex31d542c82b

214031321131 has 2 divisors, whose sum is σ = 214031321132. Its totient is φ = 214031321130.

The previous prime is 214031321071. The next prime is 214031321173. The reversal of 214031321131 is 131123130412.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 214031321131 - 27 = 214031321003 is a prime.

It is a super-3 number, since 3×2140313211313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (214031321531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107015660565 + 107015660566.

It is an arithmetic number, because the mean of its divisors is an integer number (107015660566).

Almost surely, 2214031321131 is an apocalyptic number.

214031321131 is a deficient number, since it is larger than the sum of its proper divisors (1).

214031321131 is an equidigital number, since it uses as much as digits as its factorization.

214031321131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 214031321131 its reverse (131123130412), we get a palindrome (345154451543).

The spelling of 214031321131 in words is "two hundred fourteen billion, thirty-one million, three hundred twenty-one thousand, one hundred thirty-one".