214033123141 has 4 divisors (see below), whose sum is σ = 216611835552. Its totient is φ = 211454410732.

The previous prime is 214033123067. The next prime is 214033123151. The reversal of 214033123141 is 141321330412.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214033123141 - 2²³ = 214024734533 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214033123151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1289356081 + ... + 1289356246.

It is an arithmetic number, because the mean of its divisors is an integer number (54152958888).

Almost surely, 2^214033123141 is an apocalyptic number.

It is an amenable number.

214033123141 is a deficient number, since it is larger than the sum of its proper divisors (2578712411).

214033123141 is an equidigital number, since it uses as much as digits as its factorization.

214033123141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2578712410.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 214033123141 its reverse (141321330412), we get a palindrome (355354453553).

The spelling of 214033123141 in words is "two hundred fourteen billion, thirty-three million, one hundred twenty-three thousand, one hundred forty-one".