2140334214131 has 2 divisors, whose sum is σ = 2140334214132. Its totient is φ = 2140334214130.

The previous prime is 2140334214127. The next prime is 2140334214143. The reversal of 2140334214131 is 1314124330412.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2140334214131 - 2² = 2140334214127 is a prime.

It is a super-2 number, since 2×2140334214131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2140334214094 and 2140334214103.

It is not a weakly prime, because it can be changed into another prime (2140334214121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070167107065 + 1070167107066.

It is an arithmetic number, because the mean of its divisors is an integer number (1070167107066).

Almost surely, 2^{2140334214131} is an apocalyptic number.

2140334214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140334214131 is an equidigital number, since it uses as much as digits as its factorization.

2140334214131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 2140334214131 its reverse (1314124330412), we get a palindrome (3454458544543).

The spelling of 2140334214131 in words is "two trillion, one hundred forty billion, three hundred thirty-four million, two hundred fourteen thousand, one hundred thirty-one".