Base | Representation |
---|---|
bin | 11111001001010110010… |
… | …001100000001010100111 |
3 | 21120121121001110112210221 |
4 | 133021112101200022213 |
5 | 240031404313022213 |
6 | 4315131550425211 |
7 | 310430435350006 |
oct | 37112621401247 |
9 | 7517531415727 |
10 | 2140341142183 |
11 | 75579385a112 |
12 | 2a698bb02207 |
13 | 126aaa9ca83a |
14 | 75843520c3d |
15 | 3aa1db3838d |
hex | 1f2564602a7 |
2140341142183 has 4 divisors (see below), whose sum is σ = 2140358528520. Its totient is φ = 2140323755848.
The previous prime is 2140341142169. The next prime is 2140341142237. The reversal of 2140341142183 is 3812411430412.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2140341142183 - 213 = 2140341133991 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2140341142783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8507185 + ... + 8755162.
It is an arithmetic number, because the mean of its divisors is an integer number (535089632130).
Almost surely, 22140341142183 is an apocalyptic number.
2140341142183 is a deficient number, since it is larger than the sum of its proper divisors (17386337).
2140341142183 is a wasteful number, since it uses less digits than its factorization.
2140341142183 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17386336.
The product of its (nonzero) digits is 18432, while the sum is 34.
Adding to 2140341142183 its reverse (3812411430412), we get a palindrome (5952752572595).
The spelling of 2140341142183 in words is "two trillion, one hundred forty billion, three hundred forty-one million, one hundred forty-two thousand, one hundred eighty-three".
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