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214041252253 = 967221345659
BaseRepresentation
bin1100011101010111011…
…0100101000110011101
3202110110220101012112011
43013111312211012131
512001324030033003
6242155034511221
721315066424333
oct3072566450635
9673426335464
10214041252253
1182857785904
1235595b95511
131725134286a
14a506c55b53
15587b00546d
hex31d5da519d

214041252253 has 4 divisors (see below), whose sum is σ = 214262598880. Its totient is φ = 213819905628.

The previous prime is 214041252199. The next prime is 214041252281. The reversal of 214041252253 is 352252140412.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 214041252253 - 213 = 214041244061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (214041252553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110671863 + ... + 110673796.

It is an arithmetic number, because the mean of its divisors is an integer number (53565649720).

Almost surely, 2214041252253 is an apocalyptic number.

It is an amenable number.

214041252253 is a deficient number, since it is larger than the sum of its proper divisors (221346627).

214041252253 is an equidigital number, since it uses as much as digits as its factorization.

214041252253 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 221346626.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 214041252253 its reverse (352252140412), we get a palindrome (566293392665).

The spelling of 214041252253 in words is "two hundred fourteen billion, forty-one million, two hundred fifty-two thousand, two hundred fifty-three".

Divisors: 1 967 221345659 214041252253