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2140432422281 is a prime number
BaseRepresentation
bin11111001001011011101…
…101101101010110001001
321120121211102020001120022
4133021123231231112021
5240032101200003111
64315145011110225
7310432624253516
oct37113355552611
97517742201508
102140432422281
1175583033520a
122a69b65a2375
13126ac38aa32a
14758516c230d
153aa26b692db
hex1f25bb6d589

2140432422281 has 2 divisors, whose sum is σ = 2140432422282. Its totient is φ = 2140432422280.

The previous prime is 2140432422223. The next prime is 2140432422287. The reversal of 2140432422281 is 1822242340412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2101804057600 + 38628364681 = 1449760^2 + 196541^2 .

It is a cyclic number.

It is not a de Polignac number, because 2140432422281 - 26 = 2140432422217 is a prime.

It is a super-2 number, since 2×21404324222812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2140432422287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1070216211140 + 1070216211141.

It is an arithmetic number, because the mean of its divisors is an integer number (1070216211141).

Almost surely, 22140432422281 is an apocalyptic number.

It is an amenable number.

2140432422281 is a deficient number, since it is larger than the sum of its proper divisors (1).

2140432422281 is an equidigital number, since it uses as much as digits as its factorization.

2140432422281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 49152, while the sum is 35.

Adding to 2140432422281 its reverse (1822242340412), we get a palindrome (3962674762693).

The spelling of 2140432422281 in words is "two trillion, one hundred forty billion, four hundred thirty-two million, four hundred twenty-two thousand, two hundred eighty-one".