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214051433 is a prime number
BaseRepresentation
bin11001100001000…
…10101001101001
3112220202221100212
430300202221221
5414244121213
633123510505
75206256441
oct1460425151
9486687325
10214051433
11aa910012
125b828435
1335466c6b
14205dd121
1513bd29a8
hexcc22a69

214051433 has 2 divisors, whose sum is σ = 214051434. Its totient is φ = 214051432.

The previous prime is 214051391. The next prime is 214051451. The reversal of 214051433 is 334150412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212343184 + 1708249 = 14572^2 + 1307^2 .

It is a cyclic number.

It is not a de Polignac number, because 214051433 - 28 = 214051177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 214051399 and 214051408.

It is not a weakly prime, because it can be changed into another prime (214051483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107025716 + 107025717.

It is an arithmetic number, because the mean of its divisors is an integer number (107025717).

Almost surely, 2214051433 is an apocalyptic number.

It is an amenable number.

214051433 is a deficient number, since it is larger than the sum of its proper divisors (1).

214051433 is an equidigital number, since it uses as much as digits as its factorization.

214051433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 214051433 is about 14630.4966764632. The cubic root of 214051433 is about 598.1903185389.

The spelling of 214051433 in words is "two hundred fourteen million, fifty-one thousand, four hundred thirty-three".