Base | Representation |
---|---|
bin | 110000101011101111110100… |
… | …000110011111101010001110 |
3 | 1001002002221210222000000112211 |
4 | 300223233310012133222032 |
5 | 211031004410031004032 |
6 | 2035213532412421034 |
7 | 63046055412232063 |
oct | 6053576406375216 |
9 | 1032087728000484 |
10 | 214112510016142 |
11 | 6224a673003351 |
12 | 2002053247777a |
13 | 926195273817a |
14 | 3ac315a772c6a |
15 | 19b48575dd747 |
hex | c2bbf419fa8e |
214112510016142 has 4 divisors (see below), whose sum is σ = 321168765024216. Its totient is φ = 107056255008070.
The previous prime is 214112510016133. The next prime is 214112510016187. The reversal of 214112510016142 is 241610015211412.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53528127504034 + ... + 53528127504037.
It is an arithmetic number, because the mean of its divisors is an integer number (80292191256054).
Almost surely, 2214112510016142 is an apocalyptic number.
214112510016142 is a deficient number, since it is larger than the sum of its proper divisors (107056255008074).
214112510016142 is a wasteful number, since it uses less digits than its factorization.
214112510016142 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107056255008073.
The product of its (nonzero) digits is 3840, while the sum is 31.
Adding to 214112510016142 its reverse (241610015211412), we get a palindrome (455722525227554).
The spelling of 214112510016142 in words is "two hundred fourteen trillion, one hundred twelve billion, five hundred ten million, sixteen thousand, one hundred forty-two".
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