Base | Representation |
---|---|
bin | 1001101111001001101011… |
… | …01010010000110111100011 |
3 | 2210210220100011102202001222 |
4 | 10313210311222100313203 |
5 | 10301300331413222042 |
6 | 113312115425245255 |
7 | 4336626164112512 |
oct | 467446552206743 |
9 | 83726304382058 |
10 | 21411312242147 |
11 | 6905539629283 |
12 | 24997a519382b |
13 | bc410270b2c9 |
14 | 540454db6679 |
15 | 271e561b12d2 |
hex | 137935a90de3 |
21411312242147 has 2 divisors, whose sum is σ = 21411312242148. Its totient is φ = 21411312242146.
The previous prime is 21411312242119. The next prime is 21411312242251. The reversal of 21411312242147 is 74124221311412.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21411312242147 is a prime.
It is not a weakly prime, because it can be changed into another prime (21411312242107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10705656121073 + 10705656121074.
It is an arithmetic number, because the mean of its divisors is an integer number (10705656121074).
Almost surely, 221411312242147 is an apocalyptic number.
21411312242147 is a deficient number, since it is larger than the sum of its proper divisors (1).
21411312242147 is an equidigital number, since it uses as much as digits as its factorization.
21411312242147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21504, while the sum is 35.
Adding to 21411312242147 its reverse (74124221311412), we get a palindrome (95535533553559).
The spelling of 21411312242147 in words is "twenty-one trillion, four hundred eleven billion, three hundred twelve million, two hundred forty-two thousand, one hundred forty-seven".
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