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214123940753 is a prime number
BaseRepresentation
bin1100011101101011001…
…0000000101110010001
3202110200122222012211012
43013122302000232101
512002011212101003
6242211151100305
721320122315562
oct3073262005621
9673618865735
10214123940753
118289a422a08
12355b9811695
1317265504878
14a513c1c169
1558833da8d8
hex31dac80b91

214123940753 has 2 divisors, whose sum is σ = 214123940754. Its totient is φ = 214123940752.

The previous prime is 214123940731. The next prime is 214123940761. The reversal of 214123940753 is 357049321412.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 192811444609 + 21312496144 = 439103^2 + 145988^2 .

It is a cyclic number.

It is not a de Polignac number, because 214123940753 - 26 = 214123940689 is a prime.

It is a super-3 number, since 3×2141239407533 (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 214123940753.

It is not a weakly prime, because it can be changed into another prime (214123940783) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107061970376 + 107061970377.

It is an arithmetic number, because the mean of its divisors is an integer number (107061970377).

Almost surely, 2214123940753 is an apocalyptic number.

It is an amenable number.

214123940753 is a deficient number, since it is larger than the sum of its proper divisors (1).

214123940753 is an equidigital number, since it uses as much as digits as its factorization.

214123940753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 41.

The spelling of 214123940753 in words is "two hundred fourteen billion, one hundred twenty-three million, nine hundred forty thousand, seven hundred fifty-three".