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21412423111153 is a prime number
BaseRepresentation
bin1001101111001011101111…
…10111111001000111110001
32210211000012120201201212111
410313211313313321013301
510301310120304024103
6113312421551125321
74336665543254614
oct467456767710761
983730176651774
1021412423111153
116905a59697638
122499a55213841
13bc424b8c6249
1454051c74417b
15271ebd99286d
hex137977df91f1

21412423111153 has 2 divisors, whose sum is σ = 21412423111154. Its totient is φ = 21412423111152.

The previous prime is 21412423111147. The next prime is 21412423111193. The reversal of 21412423111153 is 35111132421412.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14440858812769 + 6971564298384 = 3800113^2 + 2640372^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21412423111153 is a prime.

It is not a weakly prime, because it can be changed into another prime (21412423111193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10706211555576 + 10706211555577.

It is an arithmetic number, because the mean of its divisors is an integer number (10706211555577).

Almost surely, 221412423111153 is an apocalyptic number.

It is an amenable number.

21412423111153 is a deficient number, since it is larger than the sum of its proper divisors (1).

21412423111153 is an equidigital number, since it uses as much as digits as its factorization.

21412423111153 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5760, while the sum is 31.

Adding to 21412423111153 its reverse (35111132421412), we get a palindrome (56523555532565).

The spelling of 21412423111153 in words is "twenty-one trillion, four hundred twelve billion, four hundred twenty-three million, one hundred eleven thousand, one hundred fifty-three".