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214130114113 is a prime number
BaseRepresentation
bin1100011101101100100…
…1100011111001000001
3202110201002120212002011
43013123021203321001
512002014302122423
6242211531252521
721320225636656
oct3073311437101
9673632525064
10214130114113
11828a295a063
12355bb8aa141
1317266886746
14a514987c2d
155883c09b0d
hex31db263e41

214130114113 has 2 divisors, whose sum is σ = 214130114114. Its totient is φ = 214130114112.

The previous prime is 214130114063. The next prime is 214130114153. The reversal of 214130114113 is 311411031412.

214130114113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 192530521089 + 21599593024 = 438783^2 + 146968^2 .

It is a cyclic number.

It is not a de Polignac number, because 214130114113 - 237 = 76691160641 is a prime.

It is not a weakly prime, because it can be changed into another prime (214130114153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 107065057056 + 107065057057.

It is an arithmetic number, because the mean of its divisors is an integer number (107065057057).

Almost surely, 2214130114113 is an apocalyptic number.

It is an amenable number.

214130114113 is a deficient number, since it is larger than the sum of its proper divisors (1).

214130114113 is an equidigital number, since it uses as much as digits as its factorization.

214130114113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 214130114113 its reverse (311411031412), we get a palindrome (525541145525).

The spelling of 214130114113 in words is "two hundred fourteen billion, one hundred thirty million, one hundred fourteen thousand, one hundred thirteen".