Base | Representation |
---|---|
bin | 10011111100011001… |
… | …100000000010010001 |
3 | 2001021101222212100102 |
4 | 103330121200002101 |
5 | 322324042144213 |
6 | 13500533102145 |
7 | 1355445334211 |
oct | 237431400221 |
9 | 61241885312 |
10 | 21414412433 |
11 | 9099972017 |
12 | 4197787955 |
13 | 203373147b |
14 | 10720aa241 |
15 | 85500b158 |
hex | 4fc660091 |
21414412433 has 2 divisors, whose sum is σ = 21414412434. Its totient is φ = 21414412432.
The previous prime is 21414412429. The next prime is 21414412489. The reversal of 21414412433 is 33421441412.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15195985984 + 6218426449 = 123272^2 + 78857^2 .
It is a cyclic number.
It is not a de Polignac number, because 21414412433 - 22 = 21414412429 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21414412396 and 21414412405.
It is not a weakly prime, because it can be changed into another prime (21414417433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10707206216 + 10707206217.
It is an arithmetic number, because the mean of its divisors is an integer number (10707206217).
Almost surely, 221414412433 is an apocalyptic number.
It is an amenable number.
21414412433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21414412433 is an equidigital number, since it uses as much as digits as its factorization.
21414412433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 9216, while the sum is 29.
Adding to 21414412433 its reverse (33421441412), we get a palindrome (54835853845).
The spelling of 21414412433 in words is "twenty-one billion, four hundred fourteen million, four hundred twelve thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •